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Relax the implementation of MatcherCast to allow conversion of `Matcher<T>` to
`Matcher<const T&>`. They have the same match signature.

PiperOrigin-RevId: 297115843
This commit is contained in:
Abseil Team
2020-02-25 10:52:53 -05:00
committed by CJ Johnson
parent fd538161f4
commit 909b1ccfca
2 changed files with 15 additions and 7 deletions
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13
googlemock/include/gmock/gmock-matchers.h
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@@ -424,7 +424,14 @@ class MatcherCastImpl<T, Matcher<U> > {
!std::is_base_of<FromType, ToType>::value,
"Can't implicitly convert from <base> to <derived>");
return source_matcher_.MatchAndExplain(static_cast<U>(x), listener);
// Do the cast to `U` explicitly if necessary.
// Otherwise, let implicit conversions do the trick.
using CastType =
typename std::conditional<std::is_convertible<T&, const U&>::value,
T&, U>::type;
return source_matcher_.MatchAndExplain(static_cast<CastType>(x),
listener);
}
void DescribeTo(::std::ostream* os) const override {
@@ -524,8 +531,8 @@ inline Matcher<T> SafeMatcherCast(const M& polymorphic_matcher_or_value) {
template <typename T, typename U>
inline Matcher<T> SafeMatcherCast(const Matcher<U>& matcher) {
// Enforce that T can be implicitly converted to U.
GTEST_COMPILE_ASSERT_((std::is_convertible<T, U>::value),
"T must be implicitly convertible to U");
static_assert(std::is_convertible<const T&, const U&>::value,
"T must be implicitly convertible to U");
// Enforce that we are not converting a non-reference type T to a reference
// type U.
GTEST_COMPILE_ASSERT_(